SOLUTION: Let \(p_1\) be the proportion of successes in the first population and let \(p_2\) be the proportion of successes in the second population. Suppose that you are testing the hypothe

Question 1112454: Let \(p_1\) be the proportion of successes in the first population and let \(p_2\) be the proportion of successes in the second population. Suppose that you are testing the hypotheses:
\(H_0:p_1-p_2=0 \\ H_a:p_1-p_2 \neq 0\)
Futhermore suppose that \(z^*=1.73\), find and input the p-value for this test
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let \(p1\) be the proportion of successes in the first population and let \(p2\) be the proportion of successes in the second population. Suppose that you are testing the hypotheses:
H_0:p1-p2=0
H_a:p1-p2 # 0
Futhermore suppose that \(z^*=1.73\), find and input the p-value for this test
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p-value = 2*p(z > 1.73) = 2*normalcdf(1.73,100) = 0.0836
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Cheers,
Stan H.
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