SOLUTION: Let S be the event that a randomly selected college student has taken a statistics course, and let C be the event that the same student has taken a chemistry course. Suppose P(S) =

Question 1112147: Let S be the event that a randomly selected college student has taken a statistics course, and let C be the event that the same student has taken a chemistry course. Suppose P(S) = 0.35, P(C) = 0.26, and P(S ∩ C) = 0.16
Find the probability that a student has taken neither statistics nor chemistry.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let S be the event that a randomly selected college student has taken a statistics course, and let C be the event that the same student has taken a chemistry course. Suppose P(S) = 0.35, P(C) = 0.26, and P(S ∩ C) = 0.16
Find the probability that a student has taken neither statistics nor chemistry.
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Note:: (S OR C)' = S' AND C'
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S' AND C' = S' + C' - (S' OR C') = S'+C'- (S AND C)' = 0.65+0.74-0.84 = 0.55
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Cheers,
Stan H.
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