SOLUTION: Six balls are selected at random without replacement from an urn containing three white balls and five blue balls. Find the probability of the given event. (Round your answer to th

Question 1111227: Six balls are selected at random without replacement from an urn containing three white balls and five blue balls. Find the probability of the given event. (Round your answer to three decimal places.)
Two or three of the balls are white.
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Notice that P(2 or 3 White balls chosen) = 1 - P(exactly one white ball is chosen)
This is because with a sample size of 6, it is guaranteed that at least one white ball will be picked, given a set of 3 white (W) balls and 5 blue (B) balls.
P(2W or 3W) = 1 - P(1W) = 1 - 3/(8C6) = 1 - 3 / 28 = (28 - 3)/28 = 25/28 =
This problem has been around a while, so you probably have the answer by now.
Hopefully this matches.

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