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I will consider integer numbers from 201 to 500 INCLUSIVELY.
The number of such integer numbers is 500-200 = 300. (It is VERY good number,
since it is divisible by any of 4, 6, 10, 12, 20, 30, 50, 60 . . . )
Of these 300 numbers,
there are 300/4 = 75 numbers divisible by 4. Let me denote this set of numbers as Z4.
300/6 = 50 numbers divisible by 6. Let me denote this set of numbers as Z6.
300/10 = 30 numbers divisible by 10. Let me denote this set of numbers as Z10.
300/12 = 25 numbers divisible by 12. Let me denote this set of numbers as Z12.
Now I need to find the number of elements in the union set Z4 U Z6 U Z10 U Z12.
I can easily simplify my task by noticing that Z12 is just included into Z4 U Z6 (as their intersection !).
So, all I need is to find the number of elements in the union set Z4 U Z6 U Z10.
Now I will use THIS STATEMENT:
If A, B and C are finite sub-sets of the universal set U, then
|A U B U C| = |A| + |B| + |C| - |A n B| - |A n C| - |B n C| + |A n B n C|. (*)
Here |X| denotes the number of elements in a finite subset X. (And the symbol "n" denotes the intersection of sub-sets).
I will not prove this statement here (although it is absolutely elementary).
I will refer you to my lessons in this site
Counting elements in sub-sets of a given finite set
Advanced problems on counting elements in sub-sets of a given finite set
instead.
Now, from the formula (*)
|Z4 U Z6 U Z10| = |Z4| + |Z6| + |Z10| - |Z4 n Z6| - |Z4 n Z10| - |Z6 n Z10| + |Z4 n Z6 n Z10|. (**)
Here |Z4|, |Z6| and |Z10| are just known to you numbers 75, 50 and 30.
|Z4 n Z6| is the number of those integers from 201 to 500 that are divisible by 12; this number is 300/12 = 25.
|Z4 n Z10| is the number of those integers from 201 to 500 that are divisible by 20; this number is 300/20 = 15.
|Z6 n Z10| is the number of those integers from 201 to 500 that are divisible by 30; this number is 300/30 = 10.
Finally, |Z4 n Z6 n Z10| is the number of those integers from 201 to 500 that are divisible by 60; this number is 300/60 = 5.
Therefore, the formula (**) becomes
|Z4 U Z6 U Z10| = 75 + 50 + 30 - 25 - 15 - 10 + 5 = 110.
Thus the number of those integer between 201 and 500 that are divisible by 4, 6, 10 and 12 is 110.
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*** The problem is SOLVED. ***
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