SOLUTION: If three numbers from 100 to 999 are chosen at random, one at a time, find the probability that they will be chosen in increasing order.

Question 1108503: If three numbers from 100 to 999 are chosen at random, one at a time, find the probability that they will be chosen in increasing order.
Answer by ikleyn(52807) (Show Source): You can put this solution on YOUR website!
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If three numbers from 100 to 999 are chosen at random, there is ONLY ONE permutation / arrangement to get them in increasing order 
against 6 = 3! of possible arrangements.


So, the probability under the question is .

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I assume (although the problem does not state it explicitly) that every time three different numbers are chosen at random.

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