SOLUTION: Hey There I can truly use some help. Thank you so much in advance from the bottom of my heart thank you! ( I copied & paste the question) Suppose the lengths of the pregnancies

Question 1107028: Hey There I can truly use some help. Thank you so much in advance from the bottom of my heart thank you! ( I copied & paste the question)
Suppose the lengths of the pregnancies of a certain animal are approximately normally distributed with mean equals 246 days =246 days and standard deviation 22 days =22 days.
(a) What is the probability that a randomly selected pregnancy lasts less than 238 days?
The probability that a randomly selected pregnancy lasts less than 238 days is approximately?
(Round to four decimal places needed.)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
m = mean = 264.
sd = standard deviation = 22
x = score to be tested against the mean = 238

z-score = (x-m)/sd = (238-264)/22 = -1.181818182

area to the left of this z-score = .1186389847

the probability that a randomly selected pregnancy lasts less than 238 days is .1186.

the following picture shows the answer using z-scores.
the picture after that shows the answer using raw scores.

$$$

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