SOLUTION: Suppose that you are in a class of 31 students and it is assumed that approximately 16% of the population is left-handed. (a) Compute the probability that exactly five students ar

Question 1105985: Suppose that you are in a class of 31 students and it is assumed that approximately 16% of the population is left-handed.
(a) Compute the probability that exactly five students are left-handed.
(b) Compute the probability that at most four students are left-handed.
(c) Compute the probability that at least six students are left-handed.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
a. This is 31C*50.16^5*0.84^26=0.1915
b. At most 4 is
31C4*0.16^4*0.84^27=0.1861
31C3*0.16^3*0.84^28=0.1396
31C2*0.16^2*0.84^29=0.0758
next is 0.0265
0 is 0.84^31=0.0045
They add up to 0.4325 ANSWER
Count the first one for at least 6 students, and the probability of 5 and under is 0.627, so the complement is at least 6, and that is 0.373 ANSWER
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