SOLUTION: Z is a standard normal variable. Compute the requested probability when
P(-.87 ≤Z≤ 2.21)
Algebra.Com
Question 1104705: Z is a standard normal variable. Compute the requested probability when
P(-.87 ≤Z≤ 2.21)
Found 2 solutions by Boreal, jim_thompson5910:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
This can be done from a table or a calculator.
From the calculator use 2nd VARS 2 and (-0.87,2.21)
probability is 0.7943.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
I'm going to use this table (a similar one should be found in the back of your textbook)
Using that table, we can find the following:
P(Z < -0.87) = 0.1922 (see this image to see how I got the value)
P(Z < 2.21) = 0.9864 (see this image to see how I got the value)
So,
P(a < Z < b) = P(Z < b) - P(Z < a)
P(-0.87 < Z < 2.21) = P(Z < 2.21) - P(Z < -0.87)
P(-0.87 < Z < 2.21) = 0.9864 - 0.1922
P(-0.87 < Z < 2.21) = 0.7942 (which is the final answer)
The values are approximate
RELATED QUESTIONS
Z is a standard normal random variable. Compute the probability P(-2.37 ≤ z ≤ (answered by stanbon)
If the random variable z is a Standard Normal Score, what is P(-1.00 ≤ z ≤... (answered by stanbon)
If z represents a standard normal random variable, then the P( -0.16 ≤ z ≤... (answered by ewatrrr)
If z represents a standard normal random variable, then the P( -0.16 ≤ z ≤... (answered by robertb)
Let Z be a standard normal random variable. Use the calculator provided to determine the... (answered by Boreal)
10. Suppose z has a standard normal distribution. Find:
(b) P(z ≥ 1.96)
c)... (answered by Fombitz)
Given that z is a standard normal random variable, compute the following probabilities.
(answered by stanbon)
Z is the standard normal distribution. Find the indicated probability. HINT [See Example... (answered by reviewermath)
Let Z by a standard normal random variable. Solve for c.... (answered by stanbon)