SOLUTION: Please help find the answer to the question
A study of a population showed that males' body temperatures are approximately Normally distributed with a mean of 98.2 degrees Fahre
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A study of a population showed that males' body temperatures are approximately Normally distributed with a mean of 98.2 degrees Fahre
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Question 1104669: Please help find the answer to the question
A study of a population showed that males' body temperatures are approximately Normally distributed with a mean of 98.2 degrees Fahrenheit and a population standard deviation of 0.50 degrees Fahrenheit. What body temperature does a male have if he is at the 91st percentile? Draw a well-labeled sketch to support your answer. Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! This normal distribution says that 50% of the population is below 98.2 degrees and 50% of the population is above 98.2. So the median is the 50 percentile.
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The 91st percentile is the temperature that holds 91% of the temperatures below it and 9% above it.
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we let X be the temperature for the 91st percentile, then
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X = mean + standard deviation * Z
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Z value for 91st percentile is 1.34(from table of Z values)
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X = 98.2 + 0.50 * 1.34 = 98.87
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