SOLUTION: A and B are two events and P (A) = 0.6, P (B) = 0.7 and P (A or B) = 0.9 Find P (not A and B)

Question 1103534: A and B are two events and P (A) = 0.6, P (B) = 0.7 and P (A or B) = 0.9
Find P (not A and B)
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
P(A or B)=P(A)+P(B)-P(A and B)
0.9=0.6+0.7-0.4
Therefore since P(A and B) is 0.4, P not (A and B) is 0.6.
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
I read the problem differently than the other tutor.

From the given information, he correctly found that P(not(A AND B)) = 0.6.

As I read the problem, what we are supposed to find is P(not A AND B); that probability is P(B)-P(A AND B) = 0.7-0.4 = 0.3.
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