Question 1101835: A certain disease has an incidence rate of 0.6%. (This is percent of people in the population who have the disease.) The false negative rate is 6%; this is the percent of people who really have the disease, but test negative for it. The false positive rate is 1%; this is the percent of people who do not have the disease, but who test positive for it. Compute the probability that a person who tests positive actually has the disease.
Answer by jorel1380(3719)   (Show Source):
You can put this solution on YOUR website! Consider a sample size of 100000. Then, out of these 100,000, .6%, or .006 actually have the disease. That is, 600 actually have the disease. Out of these 600, 36 will test negative, 564 will test positive. Of the 99400 who don't have the disease, 994 will test positive, 98406 will test negative. The true ratio of people who have the disease, versus those with positive results, would be
564/564+994=0.362, or 36.2%
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