SOLUTION: A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee?

Question 1100947: A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A committee of five people must be selected from five men and eight women. How many different ways can selection be done if there are at least 3 women on the committee?
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3 women: 2 men:: 8C3*5C2 = 56*10 = 560 ways
4 women:: 1 man: 8C4*5 = 70*5 = 350 ways
5 women:: 0 men::8C5 = 56 ways
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Total = 560+350+56 = 966 ways
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Cheers,
Stan H.
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