SOLUTION: A die has six sides. If the die is tossed twice, calculate the probability that: a. the sum of the dots on the two die is greater than 5. b. the sum of the dots on the two die is

Question 1099614: A die has six sides. If the die is tossed twice, calculate the probability that:
a. the sum of the dots on the two die is greater than 5.
b. the sum of the dots on the two die is less than 8 and is even.
c. each of the die shows 3 dots:

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A die has six sides. If the die is tossed twice, calculate the probability that:
a. the sum of the dots on the two die is greater than 5.
Dots > 5::
Dots = 6:: 1/5;2/4;3/3;4/2;5/1---------5
Dots = 7:: 1/6; ... 6/1----------------6
Dots = 8:: 2/6; 3/6;....6/2------------5
Dots = 9:: ----------------------------4
----
Dots = 12:: ---------------------------1
Answer:: 26/36 = 13/18
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b. the sum of the dots on the two die is less than 8 and is even.
Dots = 6 -----5
Dots = 4 -----3
Dots = 2 -----1
Ans:: 9/36 = 1/4
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c. each of the die shows 3 dots:
Ans:: 1/36
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Cheers,
Stan H.
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