SOLUTION: Express the confidence interval 73.4%±6.3% in the form of a trilinear inequality. % <p<% looking for the two percents on either side of p

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Question 1099611: Express the confidence interval
73.4%±6.3% in the form of a trilinear inequality.
% looking for the two percents on either side of p

Found 2 solutions by Theo, stanbon:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
73.4% plus or minus 6.3% can be shown in the following manner.

67.1% < p < 79.7%

you subtract 6.3% from 73.4% to get the lower bound.
you add 6.3% to 73.4% to get the upper bound.


Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Express the confidence interval
73.4%±6.3% in the form of a trilinear inequality.
% looking for the two percents on either side of p
--------
73.4%-6.3% < p < 73.4+6.3%
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67.1% < p < 79.7%
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Cheers,
Stan H.
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