Let x,y,z, and w be the probabilities of the 4 regions in the Venn diagram below:P(A) = x+y = 0.3 P(B) = y+z = 0.6 P(A&B') = x = 0.1 P(AUB) = x+y+z = ?? Since x = 0.1, substitute 0.1 for x in x+y = 0.3 0.1+y = 0.3 y = 0.2 Substitute 0.2 for y in y+z = 0.6 0.2+z = 0.6 z = 0.4 P(AUB) = x+y+z = 0.1+0.2+0.4 = 0.7 <--answer It's also true that w = P(A'&B') = 1 - 0.7 = 0.3 Edwin