SOLUTION: you are given that the standing eye heights of women are normally distributed with a mean of 1524 mm and a standard deviation of 61mm A. a door peephole is placed at a height th

Question 1091256: you are given that the standing eye heights of women are normally distributed with a mean of 1524 mm and a standard deviation of 61mm
A. a door peephole is placed at a height that is uncomfortable for women with a standing eye height greater than 1615 mm, what percentage of women will find that height uncomfortable?
B. in selecting the height of a door peephole, the architect wants its height to be suitable for the highest 99% of standing eye heights of women. what standing eye height of women separates the highest 99% of standing eye heights from the lowest 1%?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
you are given that the standing eye heights of women are normally distributed with a mean of 1524 mm and a standard deviation of 61mm
A. a door peephole is placed at a height that is uncomfortable for women with a standing eye height greater than 1615 mm, what percentage of women will find that height uncomfortable?
z(1615) = (1615-1524)/61 = 1.4918
Ans: P(x > 1615) = P(z > 1.4918) = normalcdf(1.4918,100) = 0.0679
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B. in selecting the height of a door peephole, the architect wants its height to be suitable for the highest 99% of standing eye heights of women. what standing eye height of women separates the highest 99% of standing eye heights from the lowest 1%?
Find the z-value with a left-tail of 0.01
invNorm(0.01) = -2.3263
Find the corresponding height::
x = -2.3263*61+1524 = 1382.1 mm
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Cheers,
Stan H.
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