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A bag contains 4 red, 2 white and 3 blue balls. If two balls are chosen at random without replacement,
find the probability that the balls are of the same color.
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There are = = = 6 combinations to choose two red balls.
There are = 1 combination to choose two white balls.
There are = = = 3 combinations to choose two blue balls.
Thus there are 6 + 1 + 3 = 10 combinations to choose two balls of the same color.
The entire space of events is = = = = 36 combinations to choose two balls from the bag containing 4 + 2 + 3 = 9 balls.
Therefore, the probability that the balls are of the same color is = .
Solved.
About combinations and about these magic numbers you can read from the lessons
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
in this site.
Also, you have this free of charge online textbook in ALGEBRA-II in this site
- ALGEBRA-II - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Combinatorics: Combinations and permutations".
Also see the lesson
- Elementary Probability problems related to combinations
from the same online textbook.