SOLUTION: In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials fo

Question 1088976: In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcoming television shows. The network ran commercials for these shows during the Super Bowl. The day after the Super Bowl, and Advertising Group sampled 106 people who saw the commercials and found that 48 of them said they would watch one of the television shows.
Suppose you are have the following null and alternative hypotheses for a test you are running:
H0:p=0.5
Ha:p≠0.5
Calculate the test statistic, rounded to 3 decimal places
z=

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Test stat is z= p hat - 0.50/sqrt (p*(1-p))/106, p=0.5
z=(0.453-0.50)/0.04856=-0..9719, or -0.972

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