SOLUTION: Use the standard normal table to find the​ z-score that corresponds to the given percentile. If the area is not in the​ table, use the entry closest to the area. If the
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Question 1087320: Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score.
P80
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
you look for the area to the left of the z-score from the table.
i found a z-score of.84 yielded .7995 area to the left of that z-score and i found a z-score of .85 yielded .8024 area to the left of that z-score.
.7995 is closer to .80 than .8024, so the z-score chosen as the solution is a z-score of .84.
the z-score of .84 is an addition of 0.8 in column 1 with .04 in column 7
it's the intersection of the area in the row of .8 with the column of .04.
this is shown in the following picture.
the table i used is at http://www.stat.ufl.edu/~athienit/Tables/Ztable.pdf
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