SOLUTION: Last year I ran in a 10K where the average completion time was 48.1 min with a standard deviation of 6.2 min. This year, runners completed the race in an average of 45.7 min with a

Question 1086334: Last year I ran in a 10K where the average completion time was 48.1 min with a standard deviation of 6.2 min. This year, runners completed the race in an average of 45.7 min with a 7.8 min standard deviation. The distribution of running times each year was approximately normal.
a. If I completed the race in 46.0 min last year and in 43.2 minutes this year, in which year did I run a better race as compared to the rest of the field?
b. If 6578 runners were in this year�s race, how many runners beat my time?
c. What time would have gotten me into the top 25%
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Duplicate Question
See Answer 700495
RELATED QUESTIONS
Last year I ran in a 10K where the average completion time was 48.1 min with a standard... (answered by Fombitz)

Last year I ran in a 10K where the average completion time was 48.1 min with a standard... (answered by Fombitz)

Last year I ran in a 10K where the average completion time was 48.1 min with a standard... (answered by Boreal)

A runner's best time for the mile was: 4 min 53 sec in 2004 4 min 38 sec in 2005 4 min (answered by graphmatics)

The average playing time of compact discs in a large collection is 35 min, and the... (answered by edjones)

1) a battery is found to have a mean life of 219 hours with a standard deviation of 70... (answered by stanbon)

the waiting time at a certain bank is approximately normally distributed with a mean of... (answered by stanbon)

The mean preparation time for recipes in a cookbook is 47 min with a standard deviation... (answered by ewatrrr)

The mean length of Beethoven�s nine symphonies is 37 minutes; the standard deviation is... (answered by Sophietenen)