SOLUTION: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is 6Pn = 30. I can get it this far: 6! / (6-X)! = 30 6! / 30 = (6-X

Question 108475: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is 6Pn = 30. I can get it this far:
6! / (6-X)! = 30
6! / 30 = (6-X)!
24 = (6-X)! Then I can't figure out how to get X. Please help. Thanks.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
6! / (6-X)! = 30
6! / 30 = (6-X)!
-------------------
720/30 = (6-x)!
24 = (6-x)!
4! = (6-x)!
6-x = 4
x = 2
==========
Cheers,
Stan H.

RELATED QUESTIONS
I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am... (answered by stanbon)

I am having difficulty with this problem - please help me if you can. The chapter is... (answered by stanbon)

I am having difficulty with some homework problems please I have no idea how to do this. (answered by Grinnell)

(n+2)/4>-1 is the problem I am having trouble with can you explain please (answered by solver91311,checkley79)

I am having problems understanding how to show the answer to this problem. If If n(A)=... (answered by jerryguo41)

I do understand the relationship between nPr and nCr {( nPr = r!(nCr) } and all. But I am (answered by Edwin McCravy)

One of the major problems I am having with algebra, Geometry,ect. Is that I am having... (answered by vleith)

I am having trouble with a compound interest problem; investment of 680 at 4 percent... (answered by Alan3354,josgarithmetic)

I am having trouble with the algebra of this problem. If every angle of a regular polygon (answered by richard1234)