# SOLUTION: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is nP3 = 24. I can get it this far: n(n-1)(n-2)...2x1 / (n-3)(n-4)...2

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 Question 108469: I am doing permutation problems using the formula nPr = n!/(n-r)!. The problem I am having difficulty with is nP3 = 24. I can get it this far: n(n-1)(n-2)...2x1 / (n-3)(n-4)...2x1 = 24 n(n-1)(n-2) = 24 Then I'm not sure how to finish. Please help.Answer by stanbon(57290)   (Show Source): You can put this solution on YOUR website!nP3 = 24 n!/(n-3)! = 24 n(n-1)(n-2)=24 n(n^2-3n+2)=24 n^3-3n^2+2n-24=0 I graphed this and found n=4 is a solution. ============ Checking: 4P3 = 4!/(4-3)! = 4!/1! = 4! = 24 OK ============ Cheers, Stan H.