SOLUTION: Area under normal curve between 0 and 3.22 = P(0 < z < 3.22) = P(z < 3.22) – P(z < 0)=
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Question 1084560: Area under normal curve between 0 and 3.22 = P(0 < z < 3.22) = P(z < 3.22) – P(z < 0)=
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
It is 0.4994
The area less than 3.22 is 0.9994.
The area less than 0 is 0.5
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