SOLUTION: Solve the problem; z = datavalue - mean / standard deviation. Question: Scores on a test are normally distributed with a mean of 61 and a standard deviation of 5. What is the pe

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Question 1084228: Solve the problem; z = datavalue - mean / standard deviation.
Question: Scores on a test are normally distributed with a mean of 61 and a standard deviation of 5. What is the percentile for an exam score of 60? Round the percentile to the nearest tenth.
A) 40.1
B) 2.9
C) 42.1
D) -0.2

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
z=(x-mean)/sd
=(60-61)/5
=-0.2
probability of z < -0.2=0.4207.
42.1st percentile.
C.

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