SOLUTION: Let x be a discrete random variable that possesses a binomial distribution with n equals 5 and p equals 0.83.
What are the mean and standard deviation of this probability distri
Algebra.Com
Question 1083971: Let x be a discrete random variable that possesses a binomial distribution with n equals 5 and p equals 0.83.
What are the mean and standard deviation of this probability distribution?
Round your answers to three decimal places, if required.
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
population mean = 5 * 0.83 = 4.15
:
population standard deviation = square root(5 * 0.83 * (1-0.83)) = 0.8399 is approximately 0.840
:
RELATED QUESTIONS
A binomial distribution is based on n = 15 trials and success probability p = 0 4. . What (answered by mathmate)
Let X be a random variable having a binomial distribution with parameters n=25 and p=0.2... (answered by reviewermath)
Let X be a binomial random variable with n = 75 and p = 0.6
a) What is μ?
b) What... (answered by ikleyn)
Let X be a discrete random variable whose values lie in {0, 1, 2, ...} with probability... (answered by Saffana)
Suppose the random variable X has a binomial(n,U)distribution where U is uniformly... (answered by CPhill)
The random variable X has a binomial distribution with n = 7 and p = 0.44.
Calculate... (answered by ikleyn,ewatrrr,math_tutor2020)
Let x be a binomial random variable with n = 7, p = 0.2. Find the following value. (Round (answered by MathLover1,Edwin McCravy,ikleyn)
consider a binomial random variable X with n=5 and p=0.40
a. Find the probability... (answered by Boreal)
Let X be a binomial random variable with n = 12 and p = .3. Find the following:
a. P(X (answered by Solver92311,ikleyn)