Here are all rolls of the dice, the sample space, which contains 36 elements: (1,1) (1,2) (1,3) (1,4) (1,5) (1,6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) (3,1) (3,2) (3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) Since we are given that exactly one face shows 2, we reduce the sample space to contain only those rolls that have exactly one face showing 2. That is, we eliminate from the sample space all the rolls that don't have exactly one face showing 2. So the reduced sample space has only 10 elements. Count them. The ones that have sum 3 are colored red: (1,2) (2,1) (2,3) (2,4) (2,5) (2,6) (3,2) (4,2) (5,2) (6,2) So the desired conditional probability is 2 out of 10 oror Edwin