SOLUTION: A manufacturing plant produces a special kind of lightbulb.
Each light bulb produced has a 0.05 probability of being defective.
Five light bulbs are chosen at random from the p
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Question 1082448: A manufacturing plant produces a special kind of lightbulb.
Each light bulb produced has a 0.05 probability of being defective.
Five light bulbs are chosen at random from the production line.
To the nearest thousandth, what is the probability that exactly two of the five bulbs will be defective?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The probability of k successes in n independent trials where p is the probability of success on any given trial is given by:
\ =\ {{n}\choose{k}}(p)^k(1-p)^{n-k})
Where 
is the number of combinations of n things taken k at a time.
So you want \ =\ {{5}\choose{2}}(0.05)^2(1-0.05)^{5-2})
Hint: If you are unfamiliar with the notation, the value can be calculated by !)
And congratulations! You get to do your own arithmetic. Don't forget to round to 3 decimal places.
John
My calculator said it, I believe it, that settles it
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