SOLUTION: 1. Suppose that a population consists of the following families living on Melbourne Crescent. The number of children in each of these 6 families is shown in the table below.

Question 1080747: 1. Suppose that a population consists of the following families living on Melbourne Crescent. The number of children in each of these 6 families is shown in the table below. 10 MARKS
Name of Family Living on Melbourne Crescent Number of children
Lyu 1
Sylvestri 2
Ali 3
Johnson 4
Mensah 5
Mesic 4
a. If all possible samples of size 2 are selected, how many different samples are possible? __________

b. List all possible samples of size 2 and compute the mean of each sample. (2 marks)

c. Organize the sample means into a sampling distribution of the sample mean. (2 marks)

d. The mean number of children in the population equals _______________.
e. The mean of the distribution of sample means is equal to _____________.
f. Graph the relative frequency distribution for the population and for the sample means. (2 marks)

g. Compare the spread of the sampling distribution with the spread of the population. Which distribution has more variability?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose that a population consists of the following families living on Melbourne Crescent. The number of children in each of these 6 families is shown in the table below. 10 MARKS
Name of Family Living on Melbourne Crescent Number of children
Lyu 1
Sylvestri 2
Ali 3
Johnson 4
Mensah 5
Mesic 4
a. If all possible samples of size 2 are selected, how many different samples are possible? 6C2 = (6*5)/(1*2) = 15
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b. List all possible samples of size 2 and compute the mean of each sample. (2 marks)
Example of what to do to all 15 2-element samples::
Sample:: (1,3)---- mean = 2
Sample:: (1,4)---- mean = 2.5
Etc
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c. Organize the sample means into a sampling distribution of the sample mean. (2 marks)
List the 15 means you come up with.
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d. The mean number of children in the population equals
Find the mean of the set of 15 means (add them and divide by 15)
_______________.
e. The mean of the distribution of sample means is equal to _____________.
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f. Graph the relative frequency distribution for the population and for the sample means. (2 marks)
List the 15 means from lowest to highest.
List the # of times you have a given mean value (This should add up to 15)
List these frequencies from lowest to highest.
Convert each of the frequencies to a relative frequence by dividing by 15
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g. Compare the spread of the sampling distribution with the spread of the population. Which distribution has more variability?
-----
The spread of the population is greater than
the spread of the sampling distribution.
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Cheers,
Stan H.
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