SOLUTION: Let Z be a standard normal random variable. Use the calculator provided to determine the value of c such that P(c ≤ Z ≤ −1.12) = 0.0938

Question 1080725: Let Z be a standard normal random variable. Use the calculator provided to determine the value of c such that P(c ≤ Z ≤ −1.12) = 0.0938

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
it is -1.78
Use 2nd VARS 2 to get normal cdf. The first argument will be less than -1, and I started with -3, then -2, then -1.7, which overshot. I then tried -1.75, getting closer, and finished with -1.78.
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SOLUTION: Let Z be a standard normal random variable. Use the calculator provided to determine the value of c such that P(c &#8804; Z &#8804; &#8722;1.12) = 0.0938