If n = the number of cars that pump gas, then P(n=0) = 0.03 P(n=1) = 0.18 P(n=2) = 0.24 P(n=3) = 0.28 P(n=4) = 0.10 P(n≥5) = 0.17 Easy. Just add the probabilities of how many cars might pump. I'll do the first one. You do the other two:a) more than 2 cars receive gas
There could be 3, 4, or more than 5 P(n=3 or n=4 or n≥5) = P(n=3)+P(n=4)+P(n≥5) = 0.28 + 0.10 + 0.17 = 0.55 ---------- Edwin