SOLUTION: a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. in how many ways can a team of 9 be chosen for a game?

Question 1077484: a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. in how many ways can a team of 9 be chosen for a game?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
3 ways to choose a catcher
9 ways to choose a pitcher
6C4 ways to choose an infielder. I erred here the first time. 6C4=6*5/2=15
7C3 ways to choose an outfielder, which is 7*6*5*4!/4!3!, and that is 35 ways
So it is 3*9*15*35=14,175.
I erred in that there are 6 infielders that have to be used to fill 4 positions and 7 outfielders that have to be used to fill 3 positions. The first two are straight multiplication.

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