SOLUTION: A sample of 469 teenage births at a large city hospital is observed for the number of births resulting in twins. the 95% confidence interval for the proportion for all births among

Question 1076088: A sample of 469 teenage births at a large city hospital is observed for the number of births resulting in twins. the 95% confidence interval for the proportion for all births among teenage girls in twins was estimated to be (0.006, 0.026).
What is the sample proportion of teenage births resulting in twins?
What is the margin of error for this interval?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The 95% interval came from p hat +/- sqrt (p*(1-p))/469
Half the interval width is 0.01
The sample proportion will be in the middle or 0.016 or 1.6%
The margin of error is the interval width or +/-0.01.
Check by using 0.016+/- sqrt (p*(1-p)/469)

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