SOLUTION: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws?
My Attempt: I first
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Question 1069711: Question: A basketball player has a 50% chance of making each free throw. What is the probability that the player makes at least two out of six free throws?
My Attempt: I first found (1/2)^6 , because we have 6 "spots" or free throws.
Since finding 2,4,5,6 all work, I found in how many combinations can he make each of those events...15+40+15+6+1=77... My answer then would be 77/64. But the probability has to be less than 1....Where might have I went wrong?
Thanks in Advance!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
So then,
<--- You had 40, that was your mistake.
At least two means two through six,
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