SOLUTION: Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve.

Question 1066859: Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve.

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the standard score (z) such that the area above the mean and below z is about 34% of the area under the normal curve.
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Sketch a normal curve with horizontal axis being z-values.
Make the mean as z = 0 in the middle of the z-axis.
Shade the area to the left of z = 0 and the some area to the
right of z = 0 approximating 0.34.
The total shaded area is 0.50+0.34 = 0.84
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Use your z-chart to find the z-value corresponding to
0.34 area to the right of z = 0. That chart value is 1.
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OR use a TI-84 calculator to find the answer as follows:
That z-value has a left tail of 0.50+0.34 = 0.84
Ans: z = InvNorm(0.84) = 1
Note:: The calculator gives an answer of 0.994457..
I rounded that off to z = 1.
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Cheers,
Stan H.
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