SOLUTION: Two dice are rolled. What is the probability that: a. the numbers that come up have a sum of at least 3? b. the numbers that come up have a sum of 4 or 10? c. the numbers that c

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Question 1064139: Two dice are rolled. What is the probability that:
a. the numbers that come up have a sum of at least 3?
b. the numbers that come up have a sum of 4 or 10?
c. the numbers that come up are both odd or have a sum of at least 8?
d. one number is odd and the other is even or the numbers have a sum of at least 10?

Answer by Edwin McCravy(20066)   (Show Source): You can put this solution on YOUR website!
Two dice are rolled. What is the probability that:
There are 36 possible rolls. I'll color the "successful" \
rolls red in each case.

a. the numbers that come up have a sum of at least 3?
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Count the red ones. That's 35 out of 36 for a 
probability of 35/36.

b. the numbers that come up have a sum of 4 or 10?
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

Count the red ones. That's 6 out of 36 for a 
probability of 6/36, which reduces to 1/6.

c. the numbers that come up are both odd or have a sum of at least 8?
(1,1) (1,2) (1,3) (1,4) (1,5)  (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) 

Count the red ones. That's 21 out of 36 for a 
probability of 21/36, which reduces to 7/12.

d. one number is odd and the other is even or the numbers have a sum of at least 10?
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6) 

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6) 

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6) 

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) 

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6) 

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Count the red ones. That's 22 out of 36 for a 
probability of 11/18.

Edwin

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