SOLUTION: Two urns contain white balls and yellow balls. The first urn contains 2 white balls and 7 yellow balls and the second urn contains 3 white balls and 10 yellow balls. A ball is draw

Question 1060502: Two urns contain white balls and yellow balls. The first urn contains 2 white balls and 7 yellow balls and the second urn contains 3 white balls and 10 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Urn1: 2W & 7y
Urn2: 3W & 10y
P1 = P(Urn1 -> white ball)
P2 = P(Urn2 -> white ball)
:
P = P1*P2 (P is the probability that both balls will be white)
Now,
In urn1, there are 9 balls in total, with 2 of them white:
P1 = 2/9
In urn2 there are 13 balls in total, with 3 of them white:
P2 = 3/13
:
P = P1 * P2
P = (2/9)*(3/13)
P = 2/39 or in percentage 5.13%
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