SOLUTION: A box contains 6 black balls, 16 orange balls, and 8 white balls. Two balls are selected randomly. What is the probability that: a) One of them is black. b) The balls are not bl

Question 1060177: A box contains 6 black balls, 16 orange balls, and 8 white balls. Two balls are selected randomly.
What is the probability that:
a) One of them is black.
b) The balls are not black.
c) First ball is orange and second ball is white.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
6B
16 O
8 W
30 balls
probability 1 is black is 1-(neither is black+both are black)
neither is (24/30*23/29)=(4/5)(23/29)=92/145 ANSWER b.
both are is (6/30)*(5/29)=(1/5)(5/29)=(1/29) or 5/145
So one of them is =1-97/145, or 48/145. ANSWER a.
--------------------------------
For c, 16/30*8/29=8/15*8/29=64/435
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