SOLUTION: widget A = 6 widget B = 10 (Total widgets = 16) With 6 random samples of the total... What is the probability that, of the random sample, at least 4 widgets were from B? F

Question 1058347: widget A = 6
widget B = 10
(Total widgets = 16)
With 6 random samples of the total...
What is the probability that, of the random sample, at least 4 widgets were from B?
Find the probability mass function of the number of widget A of the random sample.

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
This would be 6C2*10C4/16C6; 6C2 is 6 choose 2 or 6!/2!4!; nCp is n!/p!(n-p)!
That is 15*210/8008=3150/8008=0.3934
P(A=x) is 10C(6-x)*6Cx/524,160, where the denominator is 16*15*14*13*12.
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