SOLUTION: Suppose that in a key punching of 80 column IBM cards, the arithmetic mean number of mistakes per card is 0.3. What percent of cards will have (i) no mistake, (ii) one mistake (iii

Question 1058198: Suppose that in a key punching of 80 column IBM cards, the arithmetic mean number of mistakes per card is 0.3. What percent of cards will have (i) no mistake, (ii) one mistake (iii) two mistakes?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
random, proportional to number, could be infinite, discrete
Poisson distribution with parameter 0.3
e^(-lambda)*lambda^x/x!
For 0, it is e^(-0.3)=0.7408
for 1 it is 0.7408(0.3)=0.2222
for 2 it is 0.7408*(0.3^2)/2=0.0334
RELATED QUESTIONS
Anil stole his friend's ATM cum debit card. He knows that the password of the card is of... (answered by ikleyn,MathTherapy)

Suppose that you take all of the black cards out of a standard deck of 52 cards and... (answered by Edwin McCravy)

Suppose that you take all of the black cards out of a standard deck of 52 cards and... (answered by stanbon)

For a game,Patricia must roll a die and draw a card from a deck of 26 cards, with each... (answered by ewatrrr)

A deck of cards contains 52 cards, 13 different cards in each suit. One card is drawn.... (answered by jim_thompson5910)

given a standard deck of 52 cards. what is the probability that drawing one card: you... (answered by Fombitz,fractalier)

Suppose two cards are drawn from a standard deck of cards. Find the probability that the (answered by Fombitz)

Find the number of possible 5-card hands that contain the cards specified. The cards are... (answered by shree840)

Suppose that you randomly draw one card from a standard deck of 52 cards. After writing... (answered by ikleyn)