SOLUTION: A sample of two balls is drawn from an urn containing 2 white and 3 red balls. Suppose A and B are two events, described as A = sample contains at least one white ball B = samp

Question 1057669: A sample of two balls is drawn from an urn containing 2 white and 3 red balls. Suppose A and B are two events, described as
A = sample contains at least one white ball
B = sample contains balls of both colors
Determine if A and B are independent events.
I figured that the Probability of A is .7 and I'm unsure if the probability of B is either .3 or .6, but how do you figure out if they're independent or not?
Answer by solve_for_x(190) (Show Source): You can put this solution on YOUR website!
P(A) = P(white, red) + P(red, white) + P(white, white) = (2/5)(3/4) + (3/5)(2/4) + (2/5)(1/4) = 14/20 = 0.70

P(B) = P(white, red) + P(red, white) = (2/5)(3/4) + (3/5)(2/4) = 12/20 = 0.60

P(A and B) = P(at least one white, and one of each color) = P(white, red) + P(red, white) = P(B) = 0.6

If the two events are independent, then P(A and B) = P(A) * P(B).

P(A) * P(B) = 0.7 * 0.6 = 0.42 ≠ 0.6

Thus, P(A and B) ≠ P(A) * P(B), so the two events are not independent.
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