SOLUTION: the waiting time x at a certain bank is approximately normally distributed with a mean of 3.7 minutes and a standard deviation of 1.4 minutes. find the 75th percentile for wait

Question 1055026: the waiting time x at a certain bank is approximately normally distributed with a mean of 3.7 minutes and a standard deviation of 1.4 minutes.
find the 75th percentile for waiting times at this bank.
Find the probability that a customer has to wait more than 6 minutes.
I believe the probability is 0.05 or 5 percent for this one but I'm not sure.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
mean of 3.7 minutes and a standard deviation of 1.4 minutes

the 75th percentile for waiting times at this bank: z = invNorm(.75) = .6745
x = 4.7 always round Up for these
|
P(x > 6) = P( )
Find z and then find P(z > value found) = normalcdf(value found, 100) 100 a placeholder
z = 1.6429
P(z > 1.6429) = normalcdf(1.6429, 100) = .05 0r 5%

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