SOLUTION: An instructor gives a 100 point exam in which the grades are normally distributed. The mean is 60 and the standard deviation is 10. If there are 5% A's and 5% F's, 15% B's and 15%

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Question 1053959: An instructor gives a 100 point exam in which the grades are normally distributed. The mean is 60 and the standard deviation is 10. If there are 5% A's and 5% F's, 15% B's and 15% D's and 60% C, find the scores that divide the distribution into those categories.
Mainly, I don't understand how to do this:
The z-score below which 5% of the scores lie is -1.64485
The z-score above which 5% of the scores lie is +1.64485.
How do you find the 1.64485? Step by step processes will be helpful for everything!
Thank you!

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Need to Know:
z = invNorm(Percentage). Percentage listed as a decimal for arithmetic purposes.
That Percentage being to the Area under the standard Normal Curve to the left of that z - value
Ex: Just a Visual of areas left of the Green Lines for various z-values

mean is 60 and the standard deviation is 10
highlight%28F%29 top score: invNorm(.05) = -1.64485 Use Calculator
z+=blue+%28x+-+mu%29%2Fblue%28sigma%29 0r blue%28sigma%29%2Az+%2B+mu=blue+%28x%29
blue%2810%29%2Az+%2B+60=blue+ Top F score
highlight%28A%29 least score: invNorm(.95) = 1.64485 Calculator
blue%2810%29%2Az+%2B+60=blue+%28score%29
|
highlight%28D%29 least score: one more than Top F score
highlight%28D%29 top score: invNorm(.20)= z %28.15+%2B+.05%29
blue%2810%29%2Az+%2B+60=blue+%28score%29
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highlight%28C%29 least score: one more than top D .
highlight%28C%29 top score:invNorm(.80) =z .60%2B.20
blue%2810%29%2Az+%2B+60=blue+%28score%29
|
highlight%28B%29 least score: one more than top C .
highlight%28B%29 top score: One less than bottom A score