SOLUTION: The trees in a cutting block have an average diameter of 35 cm, have a standard deviation of 6 cm and are normally distributed. For appraisal purposes we need to know: a) What pro

Question 1053135: The trees in a cutting block have an average diameter of 35 cm, have a standard deviation of 6 cm and are normally distributed. For appraisal purposes we need to know:
a) What proportion of trees is less than 25 cm in diameter (for pulp mill use)?
b) What proportion of trees is greater than or equal to 25 cm and less than or equal to 40 cm (for sawmill use)?
c) What proportion of trees is greater than 40 cm (for plywood use)?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
mean of 35 cm, have a standard deviation of 6 cm
TI syntax is normalcdf(smaller, larger, �, σ).
P(x < 25) = normalcdf( 1, 25, 35, 6) 1 a placeholder
P(25 ≤ x ≤ 40)= normalcdf( 25, 10, 35, 6)
P(x>40) = = normalcdf( 40,100, 35, 6) 100 a placeholder
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