SOLUTION: The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assume the distribution of amounts purchased follows the

Question 1053091: The mean amount purchased by a typical customer at Churchill's Grocery Store is $26.00 with a standard deviation of $6.00. Assume the distribution of amounts purchased follows the normal distribution. For a sample of 62 customers, answer the following questions.

a.
What is the likelihood the sample mean is at least $27.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)

Probability

b.
What is the likelihood the sample mean is greater than $25.00 but less than $27.00? (Round z value to 2 decimal places and final answer to 4 decimal places.)

Probability
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
$26.00 with a standard deviation of $6.00
TI syntax is normalcdf(smaller, larger, �, σ).
P(x >= 27) = normalcdf(27, 100, 26, 6) 100 a placeholder
|
P(25 ≤ x ≤ 27) = normalcdf(25, 27, 26, 6)
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