SOLUTION: A bag contains 3 red balls and 33 blue balls. 2 balls are selected at random. Find the probability of selecting 2 red balls.
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Question 1052838: A bag contains 3 red balls and 33 blue balls. 2 balls are selected at random. Find the probability of selecting 2 red balls.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
It depends. Did you select a ball, check its color, replace it, and then select the second ball? Or did you select two balls without replacement?
If you replaced the first ball, then, if A is the event that two red balls are selected, \ =\ \left(\frac{1}{11}\right)\left(\frac{1}{11}\right)\ =\ \frac{1}{121})
If you selected two without replacement then \ =\ \left(\frac{1}{11}\right)\left(\frac{1}{16}\right)\ =\ \frac{1}{176})
John
My calculator said it, I believe it, that settles it
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