SOLUTION: find the bone density scores that can be used as cutoff values seperating the most extreme 1% of all scores test scores normally distributed, mean of 0, standard deviation of 1

Question 1051461: find the bone density scores that can be used as cutoff values seperating the most extreme 1% of all scores
test scores normally distributed, mean of 0, standard deviation of 1
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the bone density scores that can be used as cutoff values seperating the most extreme 1% of all scores
test scores normally distributed, mean of 0, standard deviation of 1
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Lower limit:: z = invNorm(0.01) = -2.5758
Upper limit:: z = invNorm(0.99) = 2.5758
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Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
.01/2 = .005 on each side
invNorm(.005) = -2.576
invNorm(.995) = 2.576
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