SOLUTION: If a single die is rolled 5 times, what is the probability that it lands on 2 the first, third and fourth rolls, but not on either of the other rolls?

Question 1049912: If a single die is rolled 5 times, what is the probability that it lands on 2 the first, third and fourth rolls, but not on either of the other rolls?
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If a single die is rolled 5 times, what is the probability that it lands on 2 the first, third and fourth rolls, but not on either of the other rolls?
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Ans:: (1/6)^3*(5/6)^3 = 125/6^6 = 0.0027
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Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
P = (1/6)(5/6)(1/6)(1/6)(5/6)
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