SOLUTION: In a class of 100 people, 25 own fords, 20 own dodges, 13 own toyotas, 10 own both fords and dodges, 8 own fords and toyotas, 5 own dodges and toyotas, and 4 own all three. If a pe

Question 1049719: In a class of 100 people, 25 own fords, 20 own dodges, 13 own toyotas, 10 own both fords and dodges, 8 own fords and toyotas, 5 own dodges and toyotas, and 4 own all three. If a person selected at random from the class, what is the probability he or she does not own any of these vehicles? Use a venn diagram.
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
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In a class of 100 people, 25 own fords, 20 own dodges, 13 own toyotas, 10 own both fords and dodges, 8 own fords and toyotas, 5 own dodges and toyotas, and 4 own all three. If a person selected at random from the class, what is the probability he or she does not own any of these vehicles? Use a venn diagram.
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Similar problem was solved in
https://www.algebra.com/statistics/Binomial-probability/Binomial-probability.faq.question.1048656.html

https://www.algebra.com/statistics/Binomial-probability/Binomial-probability.faq.question.1048656.html

Apply the same logic.

The numbers are

100 - [25 + 20 + 13 - (10 + 8 + 5) + 4] = 61.

So, the number of people in the class who does not own any of these vehicles is 61.

Therefore, the answer to the question is .

The formula we used is well known in the elementary set theory.
Its proof is very straightforward and simple.
See, for example, the lesson
    - Advanced problems on counting elements in sub-sets of a given finite set
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook in the topic "Miscellaneous word problems" of the section "Word problems".

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