A bag contains 10 red marbles, 7 green marbles, 9 black marbles.
If one marble is drawn from the bag but not replaced, what is
the probability of drawing a red marble then a black marble?
There are 10+7+9=26 marbles. There are 10 red marbles.
Therefore 10 times out of 26 we will draw a red marble
first. That's 10/26ths of the time or 5/13ths of the
time.
Of those 5/13ths of the time that we draw a red marble
first, we don't put it back and so there are only 25
marbles of which 9 are black. So 9 times out of 25, or
9/25ths of those 5/13ths of the time we will draw a
black marble second.
So we will succeed 9/25ths of 5/13ths of the time.
That's
So we will succeed 9/65ths of the time.
Edwin