SOLUTION: A bag of M&M's has 8 red, 5 green, 6 blue, and 7 yellow M&M's. What is the probability of randomly picking:
(give answer as a reduced fraction)
1) a yellow?
2) a blu
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Question 1047849: A bag of M&M's has 8 red, 5 green, 6 blue, and 7 yellow M&M's. What is the probability of randomly picking:
(give answer as a reduced fraction)
1) a yellow?
2) a blue or green?
3) an orange?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
26 Tot: 8 red, 5 green, 6 blue, and 7 yellow
P(Y) = 7/26
P(B or G) = 6/26 + 5/26 = 11/26
P(Orange) = 0 Are NO orange
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